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Olympiad problem-solving technique

Complex Numbers & Coordinates in Geometry

When the synthetic route stalls, compute.

Place the circumcircle as the unit circle in C\mathbb{C}. Then ∣a∣=∣b∣=∣c∣=1|a|=|b|=|c|=1, conjugation is aˉ=1/a\bar a = 1/a, and the classical centres become formulas: the orthocentre is simply h=a+b+ch = a+b+c.

Rotation by θ\theta about the origin is multiplication by eiθe^{i\theta}, which makes spiral similarity almost trivial to write down.

Coordinates are the blunter cousin: choose axes so the most points get zeros. Neither is elegant, but on a timed paper a guaranteed computation beats an elusive synthetic insight.

Where it appears on Lemma: Level 8 (advanced configurations, olympiad geometry).

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